xml读取

Question

用什么方法把下面一段xml 里FieldName属性读出来 <BookMapping xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" BookName="ServiceRewards" DatabaseName="CDIPOptimizationSample">  <SheetMappingList>    <SheetMapping SheetName="数据表单" TableName="table1" SampleRows="0">      <CloumnMappingList>        <CloumnMapping CloumnName="单板名称" FieldName="ProjectName" AllowNull="true" />        <CloumnMapping CloumnName="所在产品" FieldName="PrintVersion" AllowNull="true" />        <CloumnMapping CloumnName="开发代表（RDPDT）" FieldName="RDPDT" AllowNull="true" />        <CloumnMapping CloumnName="HQA" FieldName="HQA" AllowNull="true" />        <CloumnMapping CloumnName="绝对规模（初始估计）" FieldName="pla-ext01" AllowNull="true" />        <CloumnMapping CloumnName="等效新增规模（初始估计）" FieldName="Npla-ext02" AllowNull="true" />    </CloumnMappingList>    </SheetMapping>  </SheetMappingList></BookMapping>

Answer 1

如果你使用 Linq，你甚至可以用 XML to Linq 的方式写。代码如下。

var elements = doc.Root.Element("SheetMappingList").Element("SheetMapping").Element("CloumnMappingList").Elements("CloumnMapping");
foreach (var element in elements)
{
    Console.WriteLine(element.Attribute("FieldName").Value);
}