function ajaxfen1(num,jsonr){ var url1=globalServer+'/workorder/kcWorkorder/list/ajax?type=1&pageNo=' var json1=jsonr $.ajax({ type:"POST", url:url1+num, async:true, data:jsonr, dataType:'json', success:function(data){ var pagedata=data var total=pagedata.totalRevenue var list=pagedata.list var html='' var pageers=Math.ceil(pagedata.count/pagedata.pageSize) $('.page-count21').html('共'+pagedata.count+'条') $('.app1').html('收入总计:'+total+'元') for (var i=0;i<list.length;i++) {大概代码是这样的。但是每次JQ都会默认帮我变成get方式。我想用post--
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