ES6继承涉及到多个变量如何解决？

Question

'use strict';class Person {    // 构造函数，实例化的时候将会被调用，如果不指定，那么会有一个不带参数的默认构造函数.    constructor(name) {        this.name = name;    }    // printout 是原型对象上的方法(函数)    personPrintOut() {        console.log('name:' + this.name);    }}// console.log(Animal('A',50));//ERROR Class constructor Animal cannot be invoked without 'new'var A = new Person('A');A.personPrintOut();// 继承class People extends Person {    constructor(name, age) { //构造函数        super(name);    //调用父类构造函数        this.age = age;    }    peoplePrintOut() {        console.log('name:' + this.name + ',age:' + this.age);    }}var B = new People('B', 20);B.peoplePrintOut();//继承class human extends People {    constructor(name, age, height) { //构造函数        super(name, age);    //调用父类构造函数        this.height = height;    }    humanPrintOut() {        console.log('name:' + this.name + ',age:' + this.age + ',height:' + this.height);    }}var C = new human('c', 20, 200);C.humanPrintOut();

Answer 1

rest参数 + 解析构

constructor(...args) {    super(...args);
}