form 表单 ajaxSubmit 提交后接收不到返回值

Question

前台代码$("#formSave").ajaxSubmit({success: function (data) {ShowMsg(data.message)if (data.success) {window.location.href = "/CouponManage/BusinessCoupon/List";}},error: function (data) {ShowMsg(data.message);}});后台代码public JsonResult UpdateSave(){Guid guid = new Guid(Request["CouponGuid"]);string Title = Request["title"];string Detial = Request["desc"];string msg = "";CouponLogic bll = new CouponLogic(this.OpertorGuid);Coupon coup = new Coupon();coup.Guid = guid;coup.Title = Title;coup.Description = Detial;bool flag = bll.UpdateCoupon(UserAccount, ChainStoreGuid, coup, out msg);return Json(new { success = flag, msg = msg });}结果直接在浏览器里面输出了 {"success":true,"message":"修改成功!"} ajax提交哪里没有办法处理结果

Answer 1

  $("#formSave").ajax({
            type: 'post', // 提交方式 get/post
            url: 'your url', // 需要提交的 url            data: {                'title': title,                'desc': desc,                'CouponGuid':CouponGuid
            },
            success: function(data) { // data 保存提交后返回的数据，一般为 json 数据                // 此处可对 data 作相关处理
                alert('提交成功！');
            }
            $(this).resetForm(); // 提交后重置表单
        });