关于依靠a数组筛选b数组内没有存在a数组元素

Question

A数组--tableSelectParams:["id","device_code","value"]B数组-- "tag_columns":[{       "column_desc": "id",                    "column_name": "id",                    "isShow": true                     },                     {                    "column_name": "device_code",                    "column_desc": "设备编号",                    "isShow": true                     },                     {                    "column_name": "companyid",                    "column_desc": "公司ID",                    "isShow": true                     },                     {                    "column_name": "addtime",                    "column_desc": "添加时间",                    "isShow": true                     },                     {                    "column_name": "value",                    "column_desc": "值",                    "isShow": true                     }                 ]请问如何找出B数组中 column_name没有和A数组元素相同的B数组对象。求帮忙看看。

Answer 1

let columns = tag_columns.filter(cur => !tableSelectParams.includes(cur.column_name))

Answer 2

// 生成映射表，避免过多的内循环
var map = tableSelectParams.reduce((p, c) => [p[c] = false, p][1])
var result = tag_columns.filter(i => map[i.column_name])