想了很久,卡在了不知道找出重复单词及个数,我放到数组里,输出计数都不太正确
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var s = 'During the ITB China 2018 held in Shanghai, COTRI presented the CTW Award 2018 in the Special Individual Recognition category to Mr. David L. Shields, Vice President, Sales of Island Routes Caribbean Adventures. CTW Award is recognized inside and outside China as the most important quality sign for the international Chinese outbound market.' var kv = {}, arr = s.split(/[ , .]/g) for (var i = 0; i < arr.length; i++) if (arr[i]) { kv[arr[i]] = (kv[arr[i]] || 0) + 1 //如果不考虑大小写用下面的 //kv[arr[i].toLowerCase()] = (kv[arr[i].toLowerCase()] || 0) + 1 } alert(JSON.stringify(kv, null, 4)) //只考虑重复的可以删除删除个数为1的 for (attr in kv) if (kv[attr] == 1) delete kv[attr] alert(JSON.stringify(kv, null, 4)) //替换in ==> 在 var kw = 'in', to = '在' s = s.replace(new RegExp('\\b' + kw + '\\b', 'gi'), to); alert(s)
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