关于一个构造方法中this()和super()的执行顺序?

Question

我在一个构造方法中调用第二个自身的构造方法,第二个自身构造方法中又包含一个super(),那么想知道在第一个自身构造方法中有没有隐式的super(),父类对象应该是优先于子类对象在堆内存里面出现的吧?最后究竟创建了几个父类对象class Person {  private String name;  private String location;  Person(String name) {    this.name = name;    location = "beijing";  }  Person(String name,String location) {    this.name = name;    this.location = location;  }  public String info() {    return      "name: "+name+      " location: "+location;  }}class Student extends Person {    private String school;    Student(String name, String school) {        this(name,"beijing", school);    }    Student(String n,String l ,String school) {        super(n,l);        this.school = school;    }    public String info() {        return super.info()+  " school: "+school;    }}public class TestTeacher {    public static void main(String[] args) {    Student s1 = new Student("C","S1");       System.out.println(s1.info());    }}

Answer 1

Student(n, s)这个构造器里显式调用this()，抑制隐式super()，追溯到Student(n, l, s)里，没有显式this()调用，则隐式调用super()，即Person(n, l)
在以上三个构造器里添加打印语句，结果如下：
Person(n, l) established
Student(n, l, s) established
Student(n, s) established
调用顺序一目了然