编程实现输入30个学生的成绩，求其平均成绩，及格，不及格成绩的人输，用数组。

Answer 1

#include<stdio.h>

#define N 30

int main()

{

int shuzu[N],i;

int pass=0,defail=0,sum=0,ave;

printf("请输入%d个人的成绩：\n",N);

for(i=0;i<N;i++)

{

scanf("%d",&shuzu[i]);

sum+=shuzu[i];

if(shuzu[i]>=60) pass++;

else if(shuzu[i]<60) defail++;

}

ave=sum/N;

printf("平均成绩为：%d\n",ave);

printf("及格人数为：%d\n",pass);

printf("不及格人数为：%d\n",defail);

return 0;

}

Answer 2

#include<stdio.h>

#define N 3

int main()

{

int shuzu[N],i;

int pass=0,defail=0,sum=0,ave;

for(i=0;i<N;i++)

{

scanf("%d",&shuzu[i]);

sum+=shuzu[i];

if(shuzu[i]>=60) pass++;

else if(shuzu[i]<60) defail++;

}

ave=sum/N;

printf("平均成绩为：%d\n",ave);

printf("及格人数为：%d\n",pass);

printf("不及格人数为：%d\n",defail);

return 0;

}