C语言编程

Answer 1

看你这个我测着头看得好累

int main()

{

    double i;

    int bon,bon1,bon2,bon4,bon6,bon10;

    printf("请输入利润i:")；

    scanf("%d",&i);

    bon1=100000*0.1;

    bon2=bon1+100000*0.075;

    bon4=bon2+200000*0.05;

    bon6=bon4+200000*0.03;

    bon10=bon6+400000*0.015;

if(i<=100000){

bon=i*0.1;

}else if(i<=200000){

bon=bon1+(i-100000)*0.075;

}

else if(i<=400000){

bon=bon2+(i-200000)*0.05;

}

else if(i<=600000){

bon=bon4+(i-400000)*0.03;

}

else if(i<=1000000){

bon=bon6+(i-600000)*0.01;

}

else{

bon=bon10+(i-1000000)*0.01;

}

printf("提成为:bon=%f",bon);

}