为何coor1用->,coor2要用. ????????????

Question

#include<iostream>#include<string>using namespace std;class Coordinate{public: void printX();    void printY();int x,y; };void Coordinate:: printY(){cout<<y<<endl;}void Coordinate:: printX(){cout<<x<<endl;}int main(void){Coordinate  *coor1=new Coordinate();coor1->x=0;coor1->y=20;coor1->printX();coor1->printY();delete coor1;coor1=NULL;Coordinate *coor2=new Coordinate[5];for(int i=0;i<5;i++){coor2[i].x=0;coor2[i].y=20;coor2[i].printX();coor2[i].printY();}delete []coor2;coor2=NULL;system("pause");}

Answer 1

Coordinate  *coor1=new Coordinate();

coor1是指针数据类型，访问成员自然用->

Coordinate *coor2=new Coordinate[5];

这里的coor2是指针数组类型，指向分配的数组空间的首地址，其中通过coor2[i](i=0,1,2,3,4)的方式来访问数组元素，单个元素都是Coordinate类型而不是Coordinate *类型，访问成员自然用.