var putYear=parseInt(prompt('请输入员工的入职年份'));
var putMonth=parseInt(prompt('请输入员工的入职年份'));
var putDate=parseInt(prompt('请输入员工入职时间'));
console.log(putYear,putMonth,putDate);
function allTime(a,b,c){
var newDate=new Date();
var outYear=newDate.setFullYear(a);
var outMonth=newDate.setMonth(b);
var outDate=newDate.setDate(c);
console.log(typeof outYear);
document.write('该员工入职时间是:'+outYear+'-'+outMonth+'-'+outDate+'<br/>');
document.write('该员工合同到期时间是:'+(outYear+3)+'-'+outMonth+'-'+outDate);
}
allTime(putYear,putMonth,putDate);如题。。。本来是想传入年月日的。但是结果却变成了很大的数字。麻烦学长们来看看~~~
1 回答
已采纳
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<!doctype html>
<html>
<head>
<meta charset="UTF-8" />
<title>Document</title>
</head>
<body>
<script>
var putYear=parseInt(prompt('请输入员工的入职年份'));
var putMonth=parseInt(prompt('请输入员工的入职年份'));
var putDate=parseInt(prompt('请输入员工入职时间'));
console.log(putYear,putMonth,putDate);
function allTime(a,b,c){
var newDate=new Date(a,b,c);
var outYear=newDate.getFullYear();
var outMonth=newDate.getMonth();
var outDate=newDate.getDate();
console.log(typeof outYear);
document.write('该员工入职时间是:'+outYear+'-'+outMonth+'-'+outDate+'<br/>');
document.write('该员工合同到期时间是:'+(outYear+3)+'-'+outMonth+'-'+outDate);
}
allTime(putYear,putMonth,putDate);
</script>
</body>
</html>望采纳，谢谢
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