为什么将数组名names改为name时，运行会出错

Question

var names = new Array();var i =0;do{    var next = window.prompt("enter","");    if(next>" ")        names[i] = next;    i++;    }while(next>" ");document.write("<h2>"+(names.length)+"names entered:");document.write("<ol>");for(i in names){    document.write("<li>"+names[i]+"<br />");    }document.write("</ol>");

Answer 1

因为name是程序保留字