<script type="text/javascript"> function SuperType(name){ this.name = name; this.colors = ["red", "blue", "green"]; } SuperType.prototype.sayName = function(){ alert(this.name); }; function SubType(name, age){ SuperType.call(this, name); this.age = age; } //---------------------------------问题在下一行------------------------------ //SubType.prototype = new SuperType();//这里我特意注释掉,然后我觉得subtype实例应该不能调用sayAge和sayName方法了,但实际能正常调用sayAge,而不能掉用sayName,为什么?? SubType.prototype.sayAge = function(){ alert(this.age); }; var instance1 = new SubType("Nicholas", 29); instance1.colors.push("black"); alert(instance1.colors); //"red,blue,green,black" //instance1.sayName(); //"Nicholas"; instance1.sayAge(); //29//调用sayAge正常运行,不会报错 var instance2 = new SubType("Greg", 27); alert(instance2.colors); //"red,blue,green" instance2.sayName(); //"Greg";//调用sayName会报错 instance2.sayAge(); //27 </script>
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