用python的SMTP发邮件出错

Question

smtplib email.mime.text MIMEText email.parser Parser email.mime.multipart MIMEMultipart sender = receivers = [] message = MIMEMultipart() message[] = sender message[] = receivers subject = message[] = subject body = (,,=).read() message.attach(MIMEText(body,)) server = smtplib.SMTP() server.starttls() server.login(sender,) text1 = message.() server.sendmail(sender,receivers,text1) server.quit()conf.txt文档内容如下修改后代码#-*- encoding: utf-8 -*-#-*- encoding: gbk -*-import smtplibfrom email.mime.text import MIMETextfrom email.parser import Parserfrom email.mime.multipart import MIMEMultipartsender = '[e-mail]'receivers = ['[e-mail]']message = MIMEMultipart()message['From'] = sendermessage['To'] = receiverssubject = 'my first email'message['Subject'] = subjectbody = open('conf.txt','rt',encoding='utf8').read()#print(type(body))message.attach(MIMEText(body,'plain'))server = smtplib.SMTP('smtp.qq.com')server.starttls()server.login(sender,"fojczcjqnawxcdhh")str = str()for i in message:    str = str + i#print(str)#for p in message:#   print(p)#print(type(text1))server.sendmail(sender,receivers,str)server.quit()

Answer 1

猴赛雷

Answer 2

简单来说，报错信息最后一条就是问题所在： ‘list' object has no attribute 'encode'。 列表没有encode 属性。

18行，body 是一个列表对象，合并成字符串就好了。