求问为什么我的程序会奔溃掉

Question

#include<iostream>using namespace std;class MyStack {public: MyStack(int Size); ~MyStack(); bool stackEmpty(); bool stackFull(); void clearStack(); int stackLength(); //char push(char elem); bool push(char elem); bool pop(char &elem); void stackTravel();private: int size; int top; char *pStack;}; MyStack::MyStack(int Size){  size=0; top=0; size = Size; pStack = new char(Size); cout<<"申请"<<size<<"个内存的空间！"<<endl;}MyStack::~MyStack(){ delete []pStack; pStack=NULL;cout<<"delete"<<endl;}bool MyStack::stackEmpty(){ if (top==0) return true; else return false;}bool MyStack::stackFull(){ if(size==top) return true; else return false;}void MyStack::clearStack(){ top = 0;//覆盖}int MyStack::stackLength(){ return  top;}bool MyStack::push(char elem){ if(stackFull()){ return false; } pStack[top]=elem; top++; return true;}bool MyStack::pop(char &elem){     if(!stackEmpty())    {        top--;        elem=pStack[top];                 return true;    }    else    {        return false;    } }void MyStack::stackTravel(){ for (int i = 0;i < top;i++) { cout << pStack[i]; } cout << endl;}int main() { MyStack pStack(5); char elem; char num[5]={'1','2','3','4','5'}; for(int i=0;i<5;i++){ pStack.push(num[i]); } //pStack.push('p'); //pStack.push('p'); pStack.pop(elem); if (pStack.stackEmpty()) { cout << "The stack is empty"<<endl; } if (pStack.stackFull()) { cout << "The stack is full" << endl; } cout << "The stack's length:" << pStack.stackLength() << endl; /*pStack.push('a'); pStack.push('p'); pStack.push('p'); pStack.push('l');*/ //pStack.push('e'); //pStack.stackTravel(); /*pStack.pop(elem); cout << elem << endl; pStack.clearStack();*/ //cout << "The stack's length:" << pStack.stackLength() << endl; return 0;}

Answer 1

sorry，不懂c

不过大体上了解一点点，要注意变量的声明和销毁，另外注意变量类型

c不比php，它是强数据类型，不能简单随意的转换数据类型

c不比java，它对内存的控制比较严格，不像java，都叫给虚拟机，不用管这些，同时java也不用考虑指针

建议多了解一点 指针，数据在内存的存放等等

Answer 2

在构造函数中，你想申请一块连续size个char内存，是不是？

pStack = new char(Size);

不过上面这代码写错了，申请一块连续内存需要在类型后用中括号 [ ]。 你写成了小括号，这样只是申请了一个char内存，其初值为size而已。