j2ee中servlet的一个新手问题，页面跳转提示The requested resource is not available.

Question

<form action="servlet_in" method="post">        <div class="hom-add-box">            <label>用户名：</label> <input type="text" id="hom-in-username">        </div>        <div class="hom-add-box">            <label>密码：</label> <input type="password" id="hom-in-password">        </div>        <div class="hom-add-box">            <label>登陆类型：</label>             <select>                <option>用户</option>                <option>管理员</option>            </select>        </div>        <div class="hom-add-box">            <input type="submit" value="登陆" id="submit" />        </div>    </form>servlet_in中dopost是这样写的：    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {        // TODO Auto-generated method stub        request.setCharacterEncoding("GB18030");        String username=request.getParameter("hom-in-username");        String password=request.getParameter("hom-in-password");        request.setAttribute("name", username);        request.setAttribute("password", password);        request.getRequestDispatcher("hom.jsp").forward(request, response);    }xml配置：<?xml version="1.0" encoding="UTF-8"?><web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">  <display-name>j2ee-demo</display-name>  <welcome-file-list>    <welcome-file>index.html</welcome-file>    <welcome-file>index.htm</welcome-file>    <welcome-file>index.jsp</welcome-file>    <welcome-file>default.html</welcome-file>    <welcome-file>default.htm</welcome-file>    <welcome-file>default.jsp</welcome-file>  </welcome-file-list>  <servlet>    <servlet-name>servlet_in</servlet-name>    <servlet-class>page.servlet_in</servlet-class>  </servlet>  <servlet-mapping>    <servlet-name>servlet_in</servlet-name>    <url-pattern>/servlet_in</url-pattern>  </servlet-mapping></web-app>

Answer 1

form的action应该是page/servlet_in吧

Answer 2

书上说，<url–pattern>的格式如果是“/computerBill”那么action就是"computerBill"