Common permutation Time Limit: 1000ms, Special Time Limit:2500ms,
Memory Limit:32768KBTotal submit users: 1060, Accepted users: 951Problem 10048 : No special
judgement Problem descriptionGiven two strings of lowercase letters, a and b, print the
longest string x of lowercase letters such that there is a permutation of x that
is a subsequence of a and there is a permutation of x that is a subsequence of
b.InputInput consists of pairs of lines. The first line of a pair contains a and
the second contains b. Each string is on a separate line and consists of at most
1,000 lowercase letters. OutputFor each subsequent pair of input lines, output a line containing x. If
several x satisfy the criteria above, choose the first one in alphabetical
order. Sample Inputpretty
women
walking
down
the
streetSample Outpute
nw
etProblem SourceUAL 1999我的代码如下 #include<iostream>#include<string> using namespace std;int main(){string a,b;while(cin>>a>>b){int c[26]={0},d[26]={0};int n1=a.length(),n2=b.length();for(int i=0;i<n1;i++){if(c[(int)a[i]-97]==0){c[(int)a[i]-97]=1;}}for(int i=0;i<n2;i++){if(d[(int)b[i]-97]==0){d[(int)b[i]-97]=1;}}for(int i=0;i<26;i++){if(c[i]!=0&&d[i]!=0)cout<<char(i+97);}cout<<endl;}}
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