int[]s={1,2,3,4,5,6};怎么反序 {6,5,4,3,2,1}
6 回答
已采纳
XhstormR
TA贡献140条经验 获得超197个赞
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import java.util.List;
public class Test {
public static void main(String[] args) {
List<Integer> list = new ArrayList<>();
int[] s = {1, 2, 3, 4, 5, 6};
for (int i : s) {
list.add(i);
}
Collections.reverse(list);
Object[] objects = list.toArray();
System.out.println(Arrays.toString(objects));
}
}代码以上,望采纳。
阿旭_
TA贡献217条经验 获得超353个赞
import java.util.Arrays;
public class Test8 {
public static void main(String[] args) {
// int[]s={1,2,3,4,5,6};怎么反序 {6,5,4,3,2,1}
int[] s = { 1, 2, 3, 4, 5, 6 };
for (int i = 0; i < s.length / 2; i++) {
s[i] = s[i] ^ s[s.length - 1 - i];
s[s.length - 1 - i] = s[i] ^ s[s.length - 1 - i];
s[i] = s[i] ^ s[s.length - 1 - i];
}
System.out.println("反序后:" + Arrays.toString(s));
}
}
AatroxC
TA贡献6条经验 获得超1个赞
import java.util.Arrays;
public class Test8 {
public static void main(String[] args) {
// int[]s={1,2,3,4,5,6};怎么反序 {6,5,4,3,2,1}
int[] s = { 1, 2, 3, 4, 5, 6 };
for (int i = 0; i < s.length / 2; i++) {
s[i] = s[i] ^ s[s.length - 1 - i];
s[s.length - 1 - i] = s[i] ^ s[s.length - 1 - i];
s[i] = s[i] ^ s[s.length - 1 - i];
}
System.out.println("反序后:" + Arrays.toString(s));
}
}
慕粉鸣少
TA贡献1条经验 获得超1个赞
public class main{
public static void main(String[] args){
int[] a={1,2,3,4,5,6};
for(int i=a.length-1;i>=0;i--){
system.out.print(a[i]);
}
}
}//一条代码即可,请采纳
qq_抱嫦娥O烤玉兔_03445798
TA贡献5条经验 获得超1个赞
int[] a = { 1, 2, 3, 4, 5, 6 };
for (int i = a.length - 1; i >= 0; i--) {
System.out.print(a[i]);
}
田心枫
TA贡献1064条经验 获得超383个赞
import java.util.ArrayList;import java.util.Collections;
public class Main {
public static void main(String[] args) {
ArrayList arrayList = new ArrayList();
arrayList.add("A");
arrayList.add("B");
arrayList.add("C");
arrayList.add("D");
arrayList.add("E");
System.out.println("反转前排序: " + arrayList);
Collections.reverse(arrayList);
System.out.println("反转后排序: " + arrayList);
}
}反转前排序: [A, B, C, D, E] 反转后排序: [E, D, C, B, A]
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