（1）（2）处的转换属于显式转换还是隐式转换，并解释该转换过程，解释（3）（4）处的转换过程？

Question

#include <iostream.h>#include "stdlib.h"class CComplex{public:CComplex(double r = 0, double i = 0){  real = r;  imag = i;}int operator int(){  return (int)real;}void Display(void){  cout << "(" << real << "," << imag << ")" << endl;}protected:double real;double imag;};class CVector{public:CVector(CComplex &obj1, CComplex &obj2, CComplex &obj3, CComplex &obj4){  objArray[0] = obj1;  objArray[1] = obj2;  objArray[2] = obj3;  objArray[3] = obj4;}friend CComplex &operator[](CVector obj, int n);private:CComplex objArray[4];};CComplex &operator[](CVector obj, int n){if(n<0 || n>3){  cout<<"Out of range!"<<endl;  exit(0);}return obj.objArray[n];}void main(){CComplex c1(1.1, 1.1);CComplex c2(2.2, 2.2);CComplex c3(3.3, 3.3);CComplex c4(4.4, 4.4);CVector v(c1,c2,c3,c4);v[0].Display();v[1].Display();v[2].Display();v[3].Display();v[0] = 5.5; ----------------------------------------------------------①v[1] = CComplex(6.6); -------------------------------------------②v[2] = int(CComplex(7.7)); --------------------------------------③v[3] = int(CComplex(8.8,9.9)); ----------------------------------④v[0].Display();v[1].Display();v[2].Display();v[3].Display();}

Answer 1

抱歉，我刚开始学，回答不了