3 回答
灬紫羽
TA贡献107条经验 获得超71个赞
首先是登陆表单：login.html
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Login</title>
</head>
<body>
<form action="dologin.php" method="post">
username:<input type="text" name="username" /><br/>
password:<input type="password" name="password" />
<input type="submit" value="提交"/>
</form>
</body>
</html>
下面是dologin.php;简单的写了一下
<?php
session_start();
$username = $_POST['username']?$_POST['username']:'';
$password = $_POST['password']?$_POST['password']:'';
$link = mysqli_connect('localhost', 'root', 'root', 'test');
mysqli_set_charset($link,'utf8');
$sql = "select password from user_dologin where username='".$username."'";
$res = mysqli_query($link,$sql);
$result = mysqli_fetch_assoc($res);
mysqli_close($link);
if($result['password'] == $password){
$_SESSION['username'] = $username;
$_SESSION['password'] = $password;//一般情况下session中不保存密码信息
header("Location: index.php");
}else{
header("Location: login.html");//密码错误跳回登陆网页
}
//下面是index.php；显示session内容
<?php
session_start();
echo "username:".$_SESSION['username']."<br/>";
echo "password:".$_SESSION['password'];
下面是浏览器页面效果
username:zhangsan
password:123456
//下面是数据库字段
id
username 用户名
password 用户密码
leavelu
TA贡献6条经验 获得超1个赞
dologin 中 $_SESSION['username'] = $_POST['username'];
index.php 中 session_start(); $username=$_SESSION['username']
世界和平ad
TA贡献14条经验 获得超4个赞
不太明白你的意思，是要在登录之后显示当前用户的名字吗？
登录成功时写入Session就好: session_start(); $_SESSION['user'] = Jack;
页面显示Session: if(isset($_SEESION['user'])){echo 'Wlcome'.$_SEESION['user']}
- 3 回答
- 0 关注
- 3192 浏览
添加回答
举报
0/150
提交
取消