hibernate 多对多 ，控制台只输出两条查询语句，没有 insert语句，困扰我一天了！

Question

//测试代码 public void test() {  Project pro1 = new Project(1001, "pro001");  Project pro2 = new Project(1002, "pro002");   Employee emp1 = new Employee(1,"name1");  Employee emp2 = new Employee(2,"name2");   pro1.getEmployees().add(emp1);  pro1.getEmployees().add(emp2);  pro2.getEmployees().add(emp1);    session.save(pro1);  session.save(pro2); }//project.hbm.xml    <class name="com.baul.entity.Project" table="PROJECT">        <id name="proid" type="int">            <column name="proid" />            <generator class="assigned" />        </id>        <property name="proname" type="java.lang.String">            <column name="proname" not-null="true" />        </property>        <set name="employees" table="proemp" cascade="all">            <key column="rproid" />            <many-to-many class="com.baul.entity.Employee" column="rempid" />        </set>    </class>//employee.hbm.xml    <class name="com.baul.entity.Employee" table="EMPLOYEE">        <id name="empid" type="int">            <column name="empid" />            <generator class="assigned" />        </id>        <property name="empname" type="java.lang.String">            <column name="empname" />        </property>        <set name="projects" table="proemp" inverse="true" >     <key column="rempid" />            <many-to-many class="com.baul.entity.Project" column="rproid" />        </set>    </class>//控制台输出结果INFO: HHH000037: Columns: [rproid, rempid]二月 29, 2016 3:45:46 下午 org.hibernate.tool.hbm2ddl.TableMetadata <init>INFO: HHH000108: Foreign keys: [fk_rproid, fk_rempid]二月 29, 2016 3:45:46 下午 org.hibernate.tool.hbm2ddl.TableMetadata <init>INFO: HHH000126: Indexes: [fk_rproid, fk_rempid]二月 29, 2016 3:45:46 下午 org.hibernate.tool.hbm2ddl.SchemaUpdate executeINFO: HHH000232: Schema update completeHibernate: select employee_.empid, employee_.empname as empname2_0_ from EMPLOYEE employee_ where employee_.empid=?Hibernate: select employee_.empid, employee_.empname as empname2_0_ from EMPLOYEE employee_ where employee_.empid=?

Answer 1

transaction.commit();没写?