求大神解答 我的代码哪里出粗了

Question

#include <stdio.h>int SumAverage(){ int score[10] = { 67, 98, 75, 63, 82, 79, 91, 66, 84 }; int i; int sum = 0; int average; for (i = 0; i < 10; i++) { sum = sum + score[i]; average = sum / 10; } printf("考试的总分是：%d", sum); printf("考试平均分是：%d", average); return 0;}int paixuchengji(){ int score[10] = { 67, 98, 75, 63, 82, 91, 66, 84 }; int i; int j; int temp; for (i = 8; i >= 0; i--) { for (j = 0; j <=i; j++) { if (score[j] < score[j + 1]) { temp = score[j]; score[j] = score[j + 1]; score[j + 1] = temp; } } } printf("\n成绩降序排序为：\n"); for (i = 0; i < 10; i++) { if (i != 9) printf("%d\n", score[i]); else printf("%d\n", score[i]); } printf("考试成绩的最高分是：%d", score[0]); printf("考试的最低成绩是：%d\n", score[9]);}int main(){ SumAverage(); paixuchengji(); return 0;}考试的总分是：705考试平均分是：70成绩降序排序为：989184827567666300考试成绩的最高分是：98考试的最低成绩是：0请按任意键继续. . .这是运行后的结果 

Answer 1

你的数组定义的有问题，int score[10] = { 67, 98, 75, 63, 82, 79, 91, 66, 84 };这里面只有9个元素，但是你创建的是一个长度为10的数组，所以最后一个元素会默认是0.

for (i = 8; i >= 0; i--)把i的初值设置为9。

if (i != 9)

printf("%d\n", score[i]);

else

printf("%d\n", score[i]);

这个代码放这没起到效果，直接printf("%d\n", score[i]);就可以了

Answer 2

#include <stdio.h>

int SumAverage()

{

int score[11] = { 67, 98, 75, 63, 82, 79, 91, 66, 84 ,65,99};

int i;

int sum = 0;

int average;

for (i = 0; i <11; i++)

{

sum = sum + score[i];

average = sum / 10;

}

printf("考试的总分是：%d", sum);

printf("考试平均分是：%d", average);

return 0;

}int paixuchengji()

{

int score[11] = { 67, 98, 75, 63, 82, 91, 66, 84 ,65,99};

int i;

int j;

int temp;

for (i = 8; i >= 0; i--)

{

for (j = 0; j <=i; j++)

{

if (score[j] < score[j + 1])

{

temp = score[j];

score[j] = score[j + 1];

score[j + 1] = temp;

}

}

}

printf("\n成绩降序排序为：\n");

for (i = 0; i < 10; i++)

{

if (i != 9)

printf("%d\n", score[i]);

else

printf("%d\n", score[i]);

}

printf("考试成绩的最高分是：%d", score[0]);

printf("考试的最低成绩是：%d\n", score[9]);

}

int main()

{

SumAverage();

paixuchengji();

return 0;

}

看加粗,倾斜部分,按照那样修改就行了.