<!DOCTYPE html><html> <head> <title> new document </title> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"/> <script type="text/javascript"> window.onload = function(){ var trs = document.getElementsByTagName('tr'); for(var i = 1; i < trs.length; i++){ trs[i].onmouseover = function(){ this.style.backgroundColor = "#f2f2f2"; }//我的想法是var color=trs[i].style.backgroundColor="#f2f2f2";// trs[i].onmouseover = color;这样是不对的但是不知道为什么 trs[i].onmouseout = function(){ this.style.backgroundColor = "#fff"; } } } </script> </head> <body> <table border="1" width="50%" id="table"> <tr> <th>学号</th> <th>姓名</th> <th>操作</th> </tr> <tr> <td>xh001</td> <td>王小明</td> <td><a href="#" onclick = "deleteItem(this);return false;" >删除</a></td> </tr> <tr> <td>xh002</td> <td>刘小芳</td> <td><a href="javasript:;" onclick = "deleteItem(this);" >删除</a></td> </tr> </table> <input type="button" value="添加一行" onclick = "addTo();"/> </body></html>
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李晓健
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window.onload = function(){
var trs = document.getElementsByTagName('tr');
for(var i = 1; i < trs.length; i++){
// trs[i].onmouseover = function(){
// //你在这里alert一下i 看看是不是你想要的值你就明白了
// this.style.backgroundColor = "#f2f2f2";
// };
//如果非要用trs[i] 可以这样试试
(function(i){
trs[i].onmouseover = function(){
trs[i].style.backgroundColor = "#f2f2f2";
}
}(i))
//我的想法是var color=trs[i].style.backgroundColor="#f2f2f2";
// trs[i].onmouseover = color;这样是不对的但是不知道为什么
trs[i].onmouseout = function(){
this.style.backgroundColor = "#fff";
}
}
}看注释
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