#include <stdio.h>
int main()
{
    /* 定义需要计算的日期 */
    int year = 2008;
    int month = 8;
    int day = 8;
    int num;
    /*
     * 请使用swtich语句，if...else语句完成本题
     * 如有想看小编思路的，可以点击左侧任务中的“不会了怎么办”
     * 小编还是希望大家独立完成哦~
     */
    if (year % 4 == 0)
        switch(month)
        {
            case 1:
            num=day;
            break;
            case 2:
            num=31 + day;
            break;
            case 3:
            num=31 + 29 + day;
            break;
            case 4:
            num=31 + 29 + 31 + day;
            break;
            case 5:
            num=31 + 29 + 31 + 30 + day;
            break;
            case 6:
            num=31 + 29 + 31 + 30 + 31 + day;
            break;
            case 7:
            num=31 + 29 + 31 + 30 + 31 + 30 + day;
            break;
            case 8:
            num=31 + 29 + 31 + 30 + 31 + 30 + 31 + day;
            break;
            case 9:
            num=31 + 29 + 31 + 30 + 31 + 30 + 31 + 31 + day;
            break;
            case 10:
            num=31 + 29 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + day;
            break;
            case 11:
            num=31 + 29 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + day;
            break;
            case 12:
            num=31 + 29 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + 30 + day;
            break;
        }
    else
    switch(month)
        {
            case 1:
            num=day;
            break;
            case 2:
            num=31 + day;
            break;
            case 3:
            num=31 + 28 + day;
            break;
            case 4:
            num=31 + 28 + 31 + day;
            break;
            case 5:
            num=31 + 28 + 31 + 30 + day;
            break;
            case 6:
            num=31 + 28 + 31 + 30 + 31 + day;
            break;
            case 7:
            num=31 + 28 + 31 + 30 + 31 + 30 + day;
            break;
            case 8:
            num=31 + 28 + 31 + 30 + 31 + 30 + 31 + day;
            break;
            case 9:
            num=31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + day;
            break;
            case 10:
            num=31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + day;
            break;
            case 11:
            num=31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + day;
            break;
            case 12:
            num=31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + 30 + day;
            break;
        }
         printf("%d年%d月%d日是该年的第%d天",year,month,day,num);
     return 0;
}

 return 0;
}

脑洞大开的时候到了，要练习才会进步