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为什么++i和I++的结果会是一样的呢

#include <stdio.h>

int main()

{

    int i,sum=0;

    i=1;

    while(i<=100)  //循环条件应该是什么呢?

    {

        sum=sum+i;

         i++ ;       //这里是不是应该改变循环变量的值

    }

    printf("100以内所有整数之和为:%d\n", sum);

    return 0;

}

#include <stdio.h>

int main()

{

    int i,sum=0;

    i=1;

    while(i<=100)  //循环条件应该是什么呢?

    {

        sum=sum+i;

         i++ ;       //这里是不是应该改变循环变量的值

    }

    printf("100以内所有整数之和为:%d\n", sum);

    return 0;

}


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0 回复 有任何疑惑可以回复我~
i++先使用,再运算。反之,先运算,再使用。
0 回复 有任何疑惑可以回复我~

这样就不一样了

sum = sum + i++;
sum = sum + ++i


0 回复 有任何疑惑可以回复我~

c程序是按顺序从上往下一步步走的,”i++;“是一个单独的代码程序,不管是++i还是i++,没到这排代码之前,i的值该多少就是多少,过了这排代码之后i的值才加1.意思大概就是这么个意思吧呵呵

0 回复 有任何疑惑可以回复我~

我是试着改了下,将i++改成++i,输出结果还是一样,所以不明为什么会一样。

0 回复 有任何疑惑可以回复我~

你的两段代码都是一样的!++i是先运算再使用i;i++是先使用i,再运算,不一样的。除非是程序语句没多大变化,从而两种写法都不影响输出结果。

0 回复 有任何疑惑可以回复我~

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为什么++i和I++的结果会是一样的呢

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