四个按钮的touch up inside为什么不能绑定到一个@IBAction方法?我试过了做不到,如果可以做到的话只需要把sender as UIButton,然后再把uibutton.selected = true.这样这四个方法明显可以合并到一起
2015-05-25
界面上可以完成，给你我的实现：
关键的地方就是需要在界面上对应的btn上设置sender.restorationIdentifier，不同的flag而已，或者使用tag也行。
import UIKit
class DetailViewController: UIViewController, UITextFieldDelegate{
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view, typically from a nib.
//让当前类处理录入域的相关处理（UITextFieldDelegate中的协议接口）：键盘回收等
todoItem.delegate = self
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
//点击界面的某个位置的时候执行
override func touchesEnded(touches: Set<NSObject>, withEvent event: UIEvent){
//取消下面的输入域的聚焦状态
todoItem.resignFirstResponder()
}
// MARK - UITextFieldDelegate
//当点击键盘右下角的确认之后该方法会被调用
func textFieldShouldReturn(textField: UITextField) -> Bool {
//取消下面的输入域的聚焦状态
todoItem.resignFirstResponder()
return true
}
@IBOutlet weak var todoItem: UITextField!
@IBOutlet weak var todoDate: UIDatePicker!
var preViewTableView: UITableView? = nil
var isTappedMenuBut = false
var lastSender: UIButton?
var selectedImageButName: String? = nil
func setTopMenuBarStatus(sender: UIButton){
if !isTappedMenuBut{
isTappedMenuBut = true
}else{
lastSender!.selected = false
}
lastSender = sender
sender.selected = true
let identifer = (lastSender?.restorationIdentifier)!
switch identifer{
case "child":
selectedImageButName = "child-selected"
case "tel":
selectedImageButName = "phone-selected"
case "shooping":
selectedImageButName = "shopping-cart-selected"
case "travel":
selectedImageButName = "travel-selected"
default:
println("没有匹配的iamge type name")
break
}
}
@IBAction func todoTypeTapped(sender: UIButton) {
if let typeFlag = sender.restorationIdentifier{
setTopMenuBarStatus(sender)
}else{
println("todoTypeTapped:: 没有匹配的iamge type name")
}
}
@IBAction func submitTapped() {
if lastSender == nil{
println("没有添加任何数据")
}else{
let todo = TodoModel(id: NSUUID().UUIDString,
image: selectedImageButName!,
title: todoItem.text,
date: todoDate.date)
//将新增的todoitem放入缓存
todos.append(todo)
//注意这个preViewTableView是上一个界面中的tableview控件，因为我用视频中的方式操作的话，会延迟渲染，也就是，append之后不会立即显示，等到append第二个回到界面1才会显示第一次append的数据，无奈，我就把上一个界面的该控件传下来，添加之后直接让其重新渲染，这个地方不知道是啥情况。
preViewTableView?.reloadData()
}
}
}
这个问题我自己google到了处理方法,在界面上好像不能绑定,但是在代码里面可以做到.只要调用UIButton的addTarget方法就可以了.代码如下:
override func viewDidLoad() {
super.viewDidLoad()
childButton.addTarget(self, action: "imageTapped:", forControlEvents: .TouchUpInside)
phoneButton.addTarget(self, action: "imageTapped:", forControlEvents: .TouchUpInside)
shoppingCartButton.addTarget(self, action: "imageTapped:", forControlEvents: .TouchUpInside)
travelButton.addTarget(self, action: "imageTapped:", forControlEvents: .TouchUpInside)
}
func resetButtons() {
childButton.selected = false
phoneButton.selected = false
shoppingCartButton.selected = false
travelButton.selected = false
}
func imageTapped(sender: AnyObject) {
resetButtons()
(sender as UIButton).selected = true
}
注意action只方法后面要加:号,如果这个方法没有参数就不要加:号.原因在这里:http://stackoverflow.com/questions/24007650/selector-in-swift
举报
