我也是这个问题，跳转不出来

你还应该在doPost()方法里面添加处理内容

public void doGet(HttpServletRequest request, HttpServletResponse response)

throws ServletException, IOException {

doPost(request, response);

}

项目重新部署一下，重启Tomcat

表单：

<form action="servlet/LoginServlet" method="post">
    <label>用户名：</label><input type="text" name="username" value=""><br>
    <label>密码：</label><input type="password" name="password" value=""><br>
    <input type="submit" value="提交">
    </form>

LoginServlet:
public void doPost(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {

        users u = new users();
        String username = request.getParameter("username");
        String password = request.getParameter("password");
        u.setUsername(username);
        u.setPassword(password);
        //判断用户名和密码是否正确
        if(u.getUsername().equals("admin") && u.getPassword().equals("admin")){
            //登录成功，跳转到login_success.jsp
            //请求重定向到login_success.jsp
            response.sendRedirect(request.getContextPath()+"/login_success.jsp");
        }else{
            //登录失败，跳转到login_failure.jsp
            response.sendRedirect(request.getContextPath()+"/login_failure.jsp");
        }
        
    }

代码贴出来啊