#include <stdio.h> int main() { int year = 2008; int month = 8; int day = 8; int sum=0; switch(month) { case 1:sum=sum+day;break; case 2:sum=sum+day+31;break; case 3:sum=sum+day+31+28;break; case 4:sum=sum+

#include <stdio.h>

int main()

{

int year = 2008;

int month = 8;

int day = 8;

int sum=0;

switch(month)

{

case 1:sum=sum+day;break;

case 2:sum=sum+day+31;break;

case 3:sum=sum+day+31+28;break;

case 4:sum=sum+day+31+28+31;break;

case 5:sum=sum+day+31+28+31+30;break;

case 6:sum=sum+day+31+28+31+30+31;break;

case 7:sum=sum+day+31+28+31+30+31+30;break;

case 8:sum=sum+day+31+28+31+30+31+30+31;break;

case 9:sum=sum+day+31+28+31+30+31+30+31+31;break;

case 10:sum=sum+day+31+28+31+30+31+30+31+31+30;break;

case 11:sum=sum+day+31+28+31+30+31+30+31+31+30+31;break;

case 12:sum=sum+day+31+28+31+30+31+30+31+31+30+31+30;break;

}

if((year%400==0)||(year%4==0&&year%100!=0)){printf("%d年%d月%d日是该年的第%d天",year,month,day,sum+1);}

else{printf("%d年%d月%d日是该年的第%d天",year,month,day,sum);}

return 0;

}

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2015-04-19

源自：C语言入门 4-17

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2 回答为什么算的答案不对int year = 2008; int month = 8; int day = 8; int i; if(year%4==0&&year%100!=0 || year%400==0) i=1; else i=0; switch(month) { case 12: day += 30; case 11: day += 31; case 10: day

3 回答int sum=0?

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#include <stdio.h> int main() { int year = 2008; int month = 8; int day = 8; int sum=0; switch(month) { case 1:sum=sum+day;break; case 2:sum=sum+day+31;break; case 3:sum=sum+day+31+28;break; case 4:sum=sum+

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#include <stdio.h> int main() { int year = 2008; int month = 8; int day = 8; int sum=0; switch(month) { case 1:sum=sum+day;break; case 2:sum=sum+day+31;break; case 3:sum=sum+day+31+28;break; case 4:sum=sum+

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#include <stdio.h> int main() { int year = 2008; int month = 8; int day = 8; int sum=0; switch(month) { case 1:sum=sum+day;break; case 2:sum=sum+day+31;break; case 3:sum=sum+day+31+28;break; case 4:sum=sum+