成功了方便大家借鉴
#include <stdio.h>
int main()
{
/* 定义需要计算的日期 */
int year = 2008;
int month = 8;
int day = 8;
/*
* 请使用switch语句，if...else语句完成本题
* 如有想看小编思路的，可以点击左侧任务中的“不会了怎么办”
* 小编还是希望大家独立完成哦~
*/
int sum=0;
if((year%4==0&&year%100!=0)||(year%100==0&&year%400==0))
{
switch(month)
{
case 1:
sum=0;
break;
case 2:
sum=31;
break;
case 3:
sum=60;
break;
case 4:
sum=91;
break;
case 5:
sum=121;
break;
case 6:
sum=152;
break;
case 7:
sum=182;
break;
case 8:
sum=213;
break;
case 9:
sum=244;
break;
case 10:
sum=274;
break;
case 11:
sum=305;
break;
case 12:
sum=335;
break;
}
sum=sum+day;
printf("%d年%d月%d日是该年的第%d天\n",year,month,day,sum);
}
else
{ switch(month)
{
case 1:
sum=0;
break;
case 2:
sum=31;
break;
case 3:
sum=60;
break;
case 4:
sum=91;
break;
case 5:
sum=121;
break;
case 6:
sum=152;
break;
case 7:
sum=182;
break;
case 8:
sum=213;
break;
case 9:
sum=244;
break;
case 10:
sum=274;
break;
case 11:
sum=305;
break;
case 12:
sum=335;
break;
}
sum=sum+day-1;
printf("%d年%d月%d日是该年的第%d天\n",year,month,day,sum);
}
return 0;
}
