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大神路过请解我的疑惑，谢谢

  sum=sum+i;  i++;

实在搞不懂这个代码到底是怎么算的？

不要香菜6754782

2021-10-27

源自：C语言入门  4-6

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慕神5269880
2022-03-10
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慕神5269880
2022-03-10


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哦阿达
2021-12-16

上面已经定义sum=0；i=1;

sum=sum+i;就是将sum+i的值赋给sum;

第一次执行就是sum=sum(0)+i(0);这个时候sum值就变成1了；

且有个i++；则i变成2；

则第二次执行就是sum=sum(1)+i(2);这个时候sum值就变成3了，也就是1+2；经过i++；则i变成3；

则第三次执行就是sum=sum(3;也就是1+2）+i(3);这个时候sum值就变成6了，也就是1+2+3;

以此类推


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#1

哦阿达

第一次执行就是sum=sum(0)+i(1)；这个时候sum值就变成1了 上面写错了，不好意思
2021-12-16 回复 有任何疑惑可以回复我~
weixin_慕前端3459176
2021-10-30

sum = 0 +1 = 1

i = 1+1 = 2


i = 2 <=100

sum = 1 + 2 = 3

i = 2 +1 = 3


i = 3 <= 100

sum = 3 + 3 = 6

i = 3 + 1 = 4


i = 4 <= 100

.

.

.

.

.


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慕用5588410
2021-10-27

将++i写前面吧

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#1

慕用5588410

哦不对，是i++
2021-10-27 回复 有任何疑惑可以回复我~
不要香菜6754782 提问者
2021-10-27

0=0+1？这也不对呀


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#1

qq_秋叶随风_dlyAJW

0+1=1啊，那有问题
2021-10-27 回复 有任何疑惑可以回复我~

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