#include <stdio.h>

int main() 

{ 

    /* 定义需要计算的日期 */

    int year = 2008;

    int month = 8;

    int day = 8;

    int sum;

    switch(month)

    {

        case 1;sum=8;break;

        case 2;sum=31+8;break;

        case 3;sum=31+29+8;break;

        case 4;sum=31+29+31+8;break;

        case 5;sum=31+29+31+30+8;break;

        case 6;sum=31+29+31+30+31+8;break;

        case 7;sum=31+29+31+30+31+30+8;break;

        case 8;sum=31+29+31+30+31+30+31+8;break;

        case 9;sum=31+29+31+30+31+30+31+31+8;break;

        case 10;sum=31+29+31+30+31+30+31+31+30+8;break;

        case 11;sum=31+29+31+30+31+30+31+31+30+31+8;break;

        case 12;sum=31+29+31+30+31+30+31+31+30+31+30+8;break;

    }

    if(year%4==0&&year%100!=0||year%400==0)

    {

        printf("是该年的第%d天",sum);

    }

    else

    {

        sum--;

        printf("是该年的第%d天",sum);

    }

    return 0;

}