for if...else 写法简单点
#include <stdio.h>
int main()
{
/* 定义需要计算的日期 */
int year = 2008;
int month = 8;
int day = 8;
int sum=0;
for(int i=1;i<month;i++){
if(i==2){
sum+=28;
if(year%400==0||(year%4==0&&year%100!=0)){
sum++;
}
}else if(i%2==0){
sum+=30;
}else{
sum+=31;
}
}
sum+=day;
printf("2008年8月8日是该年的第%d天",sum);
2020-05-12
#include<stdio.h>
int main()
{
int nian=2008,yue=8,ri=8,a=0,b,c;
if(nian%4==0)
{
b=29;
}
else
{
b=28;
}
for(c=0;c<=yue;c++)
{
switch(c)
{
case 1:
a+=0;
break;
case 2:
a+=31;
break;
case 3:
a+=b;
break;
case 4:
a+=31;
break;
case 5:
a+=30;
break;
case 6:
a+=31;
break;
case 7:
a+=30;
break;
case 8:
a+=31;
break;
case 9:
a+=31;
break;
case 10:
a+=30;
break;
case 11:
a+=30;
break;
case 12:
a+=30;
break;
}
}
a+=ri;
printf("%d年%d月%d日是该年的第%d天\n",nian,yue,ri,a);
return 0;
}
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