关于normalize函数record[i,:] != 0
record[i,:] != 0这个能获取!=0的列下标吗，大家也偶人试了没，我这不行的
1 回答
# 我改成了这样可以运行
for i in range(m):
#获取一部电影评分用户的id
ids = np.nonzero(record[i])[0]
#ids = record[i,:] != 0
rating_mean[i] = np.mean(rating[i,ids])
#rating_norm[i,ids] -= rating_mean[i]
rating_norm[i,ids] = rating[i,ids] - rating_mean[i]
print("The row is {},mean rating is {},rating user size is {}"
.format(i,rating_mean[i],ids.shape))举报
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