def square_of_sum(L):

    L1=[]

    for x in L:

        L1.append(x*x)

    return sum(L1)

print square_of_sum([1, 2, 3, 4, 5])

print square_of_sum([-5, 0, 5, 15, 25])

def square_of_sum(L):
    x = []
    h = 0
    for l in L:
        x.append(l * l)
        h += l*l
    print(x)
    return h
print (square_of_sum([1, 2, 3, 4, 5]))
print (square_of_sum([-5, 0, 5, 15, 25]))

# 功能实返回一个整数的逆序整数
# 切片
def 逆转1(整数):
       字符化整数 = str(整数)
       逆转后整数 = int(字符化整数[::-1])
       return 逆转后整数
#字符串拼接     
def 逆转2(整数):
       逆转后整数 = ''
       字符化整数 = str(整数)
       for i in 字符化整数:
           逆转后整数 = i+逆转后整数
       return 逆转后整数
 #还有其他很多办法,自己研究一下

def revershow(x=0):

  s=str(x)

    sn=[]

    reverout=''

    for i in range(len(s)):

        sn.append(s[i:i+1])

    for j in range(len(sn)) :

        reverout=reverout+sn[len(sn)-j-1]

    print (reverout)

    return