已解决
#include <stdio.h>
int main()
{
/* 定义需要计算的日期 */
int year = 2008;
int month = 8;
int day = 8;
/*
* 请使用switch语句，if...else语句完成本题
* 如有想看小编思路的，可以点击左侧任务中的“不会了怎么办”
* 小编还是希望大家独立完成哦~
*/
int flag;
int sum;
if ((year%4==0 && year%100!=0) || year%400==0)
flag=1;
else if
flag=0;
switch(month)
{
case 1:
sum=day;
printf("%d年%d月%d日是该年的第%d天",year,month,day,sum);
break;
case 2:
sum=day+31;
printf("%d年%d月%d日是该年的第%d天",year,month,day,sum);
break;
case 3:
sum=day+31+28;
printf("%d年%d月%d日是该年的第%d天",year,month,day,sum);
break;
case 4:
sum=day+31+28+31;
printf("%d年%d月%d日是该年的第%d天",year,month,day,sum);
break;
case 5:
sum=day+31+28+31+30;
printf("%d年%d月%d日是该年的第%d天",year,month,day,sum);
break;
case 6:
sum=day+31+28+31+30+31;
printf("%d年%d月%d日是该年的第%d天",year,month,day,sum);
break;
case 7:
sum=day+31+28+31+30+31+30;
printf("%d年%d月%d日是该年的第%d天",year,month,day,sum);
break;
case 8:
sum=day+31+28+31+30+31+30+31;
printf("%d年%d月%d日是该年的第%d天",year,month,day,sum);
break;
case 9:
sum=day+31+28+31+30+31+30+31+31;
printf("%d年%d月%d日是该年的第%d天",year,month,day,sum);
break;
case 10:
sum=day+31+28+31+30+31+30+31+31+30;
printf("%d年%d月%d日是该年的第%d天",year,month,day,sum);
break;
case 11:
sum=day+31+28+31+30+31+30+31+31+30+31;
printf("%d年%d月%d日是该年的第%d天",year,month,day,sum);
break;
case 12:
sum=day+31+28+31+30+31+30+31+31+30+31+30;
printf("%d年%d月%d日是该年的第%d天",year,month,day,sum);
break;
default:
printf("一年只有12个月");
break;
}
if(flag==1&&year>2)
sum++;
printf("%d年%d月%d日是该年的第%d天",year,month,day,sum);
return 0;
}
