以这节的这个思路应该怎么写时间倒数呢？初始值为10：00：00
<div class="daoshu"> <a href="">10:00:00</a> </div>
<script> var date = new Date(); </script>
慕慕0116261
2019-07-25
3 回答
<h1 id="text"></h1>
<script>
var toDate;
toDate = new Date();
toDate.setDate(toDate.getDate()+1);
toDate.setHours(10);
// 获取明天上午10点时间戳
toDate = toDate.getTime();
var t = document.getElementById('text');
setInterval(function(){
// 获取现在时间戳
now = new Date().getTime();
t.innerText = "距离明天上午10点，还有" + Math.ceil((toDate - now) / 1000) + "秒";
}, 1000);
</script>如果想要时分秒形式，自己把秒换算一下就行
var attime;
function clock() {
var time = new Date();
var hour = time.getHours();
var minute = time.getMinutes();
var second = time.getSeconds();
hour = hour > 9 ? hour : "0" + hour;
minute = minute > 9 ? minute : "0" + minute;
second = second > 9 ? second : "0" + second;
attime= hour + ":" + minute + ":" + second;
document.getElementById("clock").value = attime;
}
我觉得可以把这个字符先转成时间秒，然后递减该数值，显示字符的时候把数字再转成时分秒的格式，其他应该还有更加简单高效的办法
<script>
var hours = 10;
var minutes = 00;
var seconds = 00;
var total = hours * 3600 + minutes * 60 + seconds;
function countdown() {
var a = document.getElementById("countdown");
timestr = lessTen(Math.floor(total / 3600)) + ":" + lessTen(Math.floor(total / 60) % 60) + ":" + lessTen(total % 60);
a.innerHTML = timestr; total--; }
function lessTen(n){
if (n<10 && n >=0){
return "0" + n;
}
return n;
}
setInterval(countdown, 1000);
</script>举报
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