#include <stdio.h>
int main()
{
    /* 定义需要计算的日期 */
    int year = 2008;
    int month = 8;
    int day = 8;
    int sum =0;
    int er =0;
   
    switch(month)
    {
        if(year%4==0&&year%400==0)
        {
           er=29;
          
        }else
           er=28;
        case 1:
            sum +=day;
        case 2:
            sum +=day+31;
        case 3:
            sum +=day+er+31;
        case 4:
            sum +=day+er+31+31;
        case 5:
            sum +=day+er+31+31+30;
        case 6:
            sum +=day+er+31+31+30+31;
        case 7:
            sum +=day+er+31+31+30+31+30;
        case 8:
            sum +=day+er+31+31+30+31+30+31;
        case 9:
            sum +=day+er+31+31+30+31+30+31+30;
        case 10:
            sum +=day+er+31+31+30+31+30+31+30+31;
        case 11:
            sum +=day+er+31+31+30+31+30+31+30+31+30;
        case 12:
            sum +=day+er+31+31+30+31+30+31+30+31+30+31;   
            printf("在计算润年的时候，%d月是%d天",month,sum);
            
    }
 return 0;
}