#include <stdio.h>
int main()
{
    /* 定义需要计算的日期 */
    int year = 2008;
    int month = 8;
    int day = 8;
     int sum
    switch(month)
    case 1:sum=31+day;break;
    case 2:sum=59+day;break;
    case 3:sum=90+day;break;
    case 4:sum=120+day;break;
    case 5:sum=151+day;break;
    case 6:sum=181+day;break;
    case 7:sum=222+day;break;
    case 8:sum=252+day;break;
    case 9:sum=283+day;break;
    case 10:sum=313+day;break;
    case 11:sum=343+day;break;
    case 12:sum=374+day;break;
    if((year%4==0)&&(year%100!=0)||year%400==0))
  {
   sum=sum+1;
  }
   
   
   
   
   

 return 0;
}