这哪有问题啊
#include <stdio.h>
int main()
{
/* 定义需要计算的日期 */
int year = 2008;
int month = 8;
int day = 8;
int sum,i;
/*
* 请使用switch语句,if...else语句完成本题
* 如有想看小编思路的,可以点击左侧任务中的“不会了怎么办”
* 小编还是希望大家独立完成哦~
*/
if(year%400==0||(year%4==0&&year%100!==0))i=1;
else i=0;
switch(month)
{
case 3:sum=0;break;
case 2:sum=31;break;
case 3:sum=31+28;break;
case 4:sum=31+28+31;break;
case 5:sum=31+28+31+30;break;
case 6:sum=31+28+31+30+31;break;
case 7:sum=31+28+31+30+31+30;break;
case 8:sun=31+28+31+30+31+30+31;break;
case 9:sun=31+28+31+30+31+30+31+31;break;
case 10:sum=31+28+31+30+31+30+31+31+30;break;
case 11:sum=31+28+31+30+31+30+31+31+30+31;break;
case 12:sum=31+28+31+30+31+30+31+31+30+31+30;break;
}
sum=sum+day;
if(i==1&&month>1)sum+=1;
printf("%d年%d月%d日是这年的第几天",year,month,day,sum);
return 0;