稍微改了一下,这下啥日子都能算的出来
#include <stdio.h>
int main()
{
int year = 2008;
int month = 8;
int month1 = month;
int month2 =1;
int day = 8;
int sum=0;
for(month2 ;month2 <month1 ;month2++)
{
switch(month2 )
{
case 12:sum+=31;break;
case 11:sum+=30;break;
case 10:sum+=31;break;
case 9:sum+=30;break;
case 8:sum+=31;break;
case 7:sum+=31;break;
case 6:sum+=30;break;
case 5:sum+=31;break;
case 4:sum+=30;break;
case 3:sum+=31;break;
case 2:
if (year%4==0&&year%100!=0)
sum+=29;
else
{
sum+=28;
}
break;
case 1:sum+=31;break;
default:printf("一年只有12个月哦");break;
}
}
sum+=day;
printf("%d年%d月%d日这一天是该年第%d天",year,month1 ,day,sum);
return 0;
}