#include <stdio.h>
int main()
{
   /* 定义需要计算的日期 */
   int year = 2008;
   int month = 8;
   int day = 8;
   int sum;
   switch(month)
   {
       case 1:sum=0;break;
       case 2:sum=31;break;
       case 3:sum=31+28;break;
       case 4:sum=31+28+31;break;
       case 5:sum=31+28+31+30;break;
       case 6:sum=31+28+31+30+31;break;
       case 7:sum=31+28+31+30+31+30;break;
       case 8:sum=31+28+31+30+31+30+31;break;
       case 9:sum=31+28+31+30+31+30+31+30;break;
       case 10:sum=31+28+31+30+31+30+31+30+31;break;
       case 11:sum=31+28+31+30+31+30+31+30+31+30;break;
       case 12:sum=31+28+31+30+31+30+31+30+31+30+31;break;
   }
   //计算天数
   sum=sum+day;
   if(year%400==0&&month>2)
   sum+=1;
   else
   sum=sum;
   printf("%d年%d月%d日是该年的第%d天",year,month,day,sum);
return 0;
}