运行成功，输出错误，请检查代码中是否包含x=x*2，我这么做错了吗
#include <stdio.h>
int main()
{
int x = 10;
int y = 10;
x *= 2;
y *= 2;
printf("x=%d\n", x);
printf("y=%d\n", y);
return 0;
}
int main()
{
int x = 10;
int y = 10;
x *= 2;
y *= 2;
printf("x=%d\n", x);
printf("y=%d\n", y);
return 0;
}
qq_里宏伟_0
2018-08-30
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