#include <stdio.h>
int main()
{
    /* 定义需要计算的日期 */
    int year = 2008;
    int month = 8;
    int day = 8;
    int i,j;
    if((year%100 != 0 && year%4 == 0)||year%400 == 0)
    {
        i = 28;
    }
    else
    {
        i = 27;
    }
    switch(month)
    {
        case 1:j = day; break;
        case 2:j = 31 + day; break;
        case 3:j = 31 + i + day; break;
        case 4:j = 31 + i + 31 + day; break;
        case 5:j = 31 + i + 31 + 30 + day; break;
        case 6:j = 31 + i + 31 + 30 + 31 + day; break;
        case 7:j = 31 + i + 31 + 30 + 31 + 30 + day; break;
        case 8:j = 31 + i + 31 + 30 + 31 + 30 + 31 + day; break;
        case 9:j = 31 + i + 31 + 30 + 31 + 30 + 31 + 31 + day; break;
        case 10:j =31 + i + 31 + 30 + 31 + 30 + 31 + 31 + 30 + day; break;
        case 11:j =31 + i + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + day; break;
        case 12:j =31 + i + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + 30 + day; break;
    }
    printf("%d年%d月%d日是该年中的第%d天"), year, month, day, j);
    /*
     * 请使用switch语句，if...else语句完成本题
     * 如有想看小编思路的，可以点击左侧任务中的“不会了怎么办”
     * 小编还是希望大家独立完成哦~
     */
 return 0;
}