1 回答
#include <stdio.h>
int main()
{
int year = 2008;
int month = 8;
int day = 8;
int i,j;
if(year%100==0&&year%400==0||year%4==0&&year%100!=0)i=1;
else i=0;
switch(month)
{
case 1:j=day;break;
case 2:j=31+ day;break;
case 3:j=31+ 28+ day;break;
case 4:j=31+ 28+ 31+ day;break;
case 5:j=31+ 28+ 31+ 30+ day;break;
case 6:j=31+ 28+ 31+ 30+ 31+ day;break;
case 7:j=31+ 28+ 31+ 30+ 31+ 30+ day;break;
case 8:j=31+ 28+ 31+ 30+ 31+ 30+ 31+day;break;
case 9:j=31+ 28+ 31+ 30+ 31+ 30+ 31+ 31+ day;break;
case 10:j=31+ 28+ 31+ 30+ 31+ 30+ 31+ 31+ 30+day;break;
case 11:j=31+ 28+ 31+ 30+ 31+ 30+ 31+ 31+ 30+ 31+day;break;
case 12:j=31+ 28+ 31+ 30+ 31+ 30+ 31+ 31+ 30+ 31+ 30+ day;break;
}
if(i==1)j+=1;
printf("%d年%d月%d日是该年的第%d天",year,month,day,j);
return 0;
}
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