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各位大神们，为什么不可这样printf（“x%%y=%d\n”， 1 ）；
2017-10-20
源自：C语言入门 3-2
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双%%会是系统进入递归导致运行环境崩溃
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1 回答 printf("x%%y=%d\n",x%y );与 printf("x%y=%d\n",x%y );
2 回答#include <stdio.h> int main() { int x,y; x = 10; y = -3; printf("x+y=%d\n", x+y ); printf("x-y=%d\n", x-y ); printf("x*y=%d\n", x*y ); printf("x/y=%d\n", x/y ); printf("x%y=%d\n", x%y ); return 0;
2 回答include <stdio.h> int main() { int x,y; x = 10; y = -3; printf("x+y=%d\n", x+y ); printf("x-y=%d\n", x-y ); printf("x*y=%d\n", x*y ); printf("x/y=%d\n", x/y ); printf("x%y=%d\n", x%y ); return 0;
6 回答#include <stdio.h> int main() { int a,s,d,f,g; a=x+y; s=x-y; d=x*y;f=x/y;g=x%y;printf("x+y=%d\n", a);printf("x-y=%d\n", s);printf("x*y=%d\n", d ); printf("x/y=%d\n", f);printf("x%y=%d\n", g);return 0;}
1 回答printf("x+y=%d\n",x+y);
