求大神帮忙为何异常 catch 没有输出 a 啊难道是 String 定义 b1 求解决

public static void main(String[] args) {

// TODO Auto-generated method stub

Scanner input = new Scanner(System.in);

System.out.println("**********欢迎来到借书平台！**********");

System.out.println("输入命令：1-按照名称查找图书；2-按照序号查找图书");

String[] b = {"高数","论语","三体"};

int a = input.nextInt() ;

if(a==1){

System.out.println("输入图书名称：");

String b1 = input.next();

try{ if(b1.equals(b[0])||b1.equals(b[1])||b1.equals(b[2])){

System.out.println("book："+b1);

}

} catch(Exception e){

System.out.println("a");

慕村5803318

2017-09-17

源自：Java入门第三季 1-9

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2 回答

qq_偷猫的鱼_0
2017-09-17

package com.imooc;

import java.util.Scanner;
import java.util.Arrays;
public abstract class TuShu {

   /**
   * @param args
   */
   public static void main(String[] args) {
       // TODO Auto-generated method stub
       try {
       method1();
   } catch (Exception e) {
       // TODO Auto-generated catch block
       e.printStackTrace();
   }
   }

    public static void method1() throws Exception{
       String shu[]={"1.论语","2.高数","3.线代"};
       String name[]={"论语","高数","线代","aaa"};
       int num[]={1,2,3};
       System.out.println("所有图书："+Arrays.toString(shu));
       System.out.println("请按提示输入命令：按图书名称查询请按1；按序号查询请按2.");
       Scanner scan = new Scanner(System.in);
       int numb = scan.nextInt();
       if(numb==1){
           System.out.println("输入图书名称：");
           Scanner name1 = new Scanner(System.in);
           String nam = name1.next();
           System.out.println(nam);
           for(int i=0;i<name.length;i++){
               if(nam.equalsIgnoreCase(name[i])){
                   System.out.println("找到图书");
               }
               else {
               }
           }
       }
       else if(numb==2){
           System.out.println("请输入序号：");
           Scanner number = new Scanner(System.in);
           int nu = number.nextInt();
           for(int i=0;i<num.length;i++){
               while(nu==num[i]){
                   System.out.println("找到图书!");
               }
              }
            }
       else{
           throw new Exception("输入正确序号~！");
       }
    }
}