#include <stdio.h>
int main()
{
    /* 定义需要计算的日期 */
    int year = 2008;
    int month = 8;
    int day = 8;
    int sum;
    switch(month)
    {  
        case 1:sum=day;break;
        case 2:sum=day+31;break;
        case 3:sum=day+60;break;
        case 4:sum=day+91;break;
        case 5:sum=day+121;break;
        case 6:sum=day+152;break;
        case 7:sum=day+182;break;
        case 8:sum=day+213;break;
        case 9:sum=day+244;break;
        case 10:sum=day+274;break;
        case 11:sum=day+305;break;
        case 12:sum=day+335;break;
        default:printf("一年只有12个月");break;
    }
    if((year%4==0&&year%100!=0)||year%400==0)
        {sum=sum;}
    else
        {sum=sum-1;}
    printf("%d年%d月%d日是该年中的第%d天\n",year,month,day,sum);
    return 0;
}