j的值是怎么来的？
def count():
fs = []
for i in range(1, 4):
def f(j):
def g():
return j*j
return g
r = f (i)
fs.append(r)
return fs
f1, f2, f3 = count()
print f1(), f2(), f3()
慕村8182185
2017-08-28
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