#include <stdio.h> int main() { int x,y; x = 10; y = -3; printf("x+y=%d\n", x+y ); printf("x-y=%d\n", x-y ); printf("xy=%d\n", xy ); printf("x/y=%d\n", x/y ); printf("x%y=%d\n", x%y ); return 0;

第一遍是错的，第二遍就对了？为什么同一个答案两次不同？

慕粉2025217122

2017-03-21

源自：C语言入门 3-2

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慕粉1437597471
2017-03-21

只能说，同上，除此之外我也找不到其他错误

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Benu0
2017-03-21

#include <stdio.h>

int main()

{

int x,y;

x = 10;

y = -3;

printf("x+y=%d\n", x+y );//7

printf("x-y=%d\n", x-y );//13

printf("x*y=%d\n", x*y );//-30

printf("x/y=%d\n", x/y );//-3

printf("x%y=%d\n", x%y );//1

return 0;

}

你短一个“}”，所以错了，测试短后不管几次都是错的，而且答案一样，不会变。

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#include <stdio.h> int main() { int x,y; x = 10; y = -3; printf("x+y=%d\n", x+y ); printf("x-y=%d\n", x-y ); printf("xy=%d\n", xy ); printf("x/y=%d\n", x/y ); printf("x%y=%d\n", x%y ); return 0;

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#include <stdio.h> int main() { int x,y; x = 10; y = -3; printf("x+y=%d\n", x+y ); printf("x-y=%d\n", x-y ); printf("x*y=%d\n", x*y ); printf("x/y=%d\n", x/y ); printf("x%y=%d\n", x%y ); return 0;

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#include <stdio.h> int main() { int x,y; x = 10; y = -3; printf("x+y=%d\n", x+y ); printf("x-y=%d\n", x-y ); printf("xy=%d\n", xy ); printf("x/y=%d\n", x/y ); printf("x%y=%d\n", x%y ); return 0;

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