为何f转为双精度浮点了？
#include <stdio.h>
int main()
{
char c = 'a';
int n =c; //将c赋值给n
c=97;
float f =c; //将c赋值给f
double d =c; //将c赋值给d
printf("%d\n",n);
printf("%f\n",f);
printf("%lf\n",d);
return 0;
}
为何f转为双精度浮点了？
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#include <stdio.h>
int main()
{
char c = 'a';
int n =c; //将c赋值给n
c=97;
float f =c; //将c赋值给f
double d =c; //将c赋值给d
printf("%d\n",n);
printf("%f\n",f);
printf("%lf\n",d);
return 0;
}
为何f转为双精度浮点了？
2017-03-14
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